Ah, solving mole calculations with calcium carbonate—it's like meeting an old friend on the Margao road. For 25 g of CaCO₃, first find its molar mass: 40 + 12 + (16×3) = 100 g/mol. So moles = given mass ÷ molar mass, that is 25 ÷ 100, giving you 0.25 moles. You see, I practice these sums on my balcony with the evening breeze, rewriting them until they feel as familiar as the sound of the ferry horn. It reminds me that some things, like the sea and these formulas, remain constant even when the exams do not.
#exams#study
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