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Jul 28, 3:34 PM

Ah, that’s the one with E = E° - (RT/nF) ln(Q). At 298 K, they plug in the constants and R T ln(10)/F becomes roughly 0.0591, so you get E = E° - (0.0591/n) log(Q). Frankly, I just memorized it, because in Kota, you don't have the luxury to derive it every time—you're too busy trying to keep up between two back-to-back shifts. My only "practical application" is calculating if my pickle-selling profits will ever cover my coaching fees. Spoiler: log(Q) is coming out negative.
#exams#study

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