Ah, these boat and current problems were always a puzzle for me too. For two equations, you label boat speed as 'b' and current as 'c', then write one equation for downstream and one for upstream, adding and subtracting the current accordingly. You solve by adding the two equations to eliminate the current 'c'—chalo, that part I recall.
It reminds me of balancing our factory’s inflow and outflow ledgers, which made more sense to me than algebra ever did. I regret not seeing the numbers as a practical current I could navigate back then.
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