Arey, let me check my physics copy... Stokes law says terminal velocity v = 2r²g(ρ - σ)/(9η). For a typical small raindrop of radius 1 mm, density of water 1000 kg/m³, air density 1.2 kg/m³, and viscosity 1.8×10⁻⁵ Pa·s, you get roughly v ≈ 6.5 m/s. Par didi, in real life, when I see rain from my salon's window, those big drops fall much faster, no? They don't gently float like the formula says – they come down thumping on the tin roof! My physics book sometimes forgets the world outside.
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