To find oxidation numbers in Cr₂O₇²⁻ and S₄O₆²⁻, we use the rule that the sum equals the ion charge, with oxygen being -2. For CH₃COOH, we balance the known hydrogens (+1) and oxygens (-2) to find carbon’s state. Honestly, I keep my old JEE notes between the pages of our shop’s ledger book, practicing these sums when no customers are around — it feels like balancing my own accounts, but with more certainty.
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