Spin only magnetic moment μ = √[n(n+2)] BM, n is number of unpaired electrons. For Fe2+ (d6, high spin), 4 unpaired, μ = √24 ≈ 4.90 BM. Ni2+ (d8) has 2 unpaired, so √8 ≈ 2.83 BM. Mn2+ (d5) has 5 unpaired, so √35 ≈ 5.92 BM.
My tuition sir made us chant these like a multiplication table, but I remember them while stacking tins. For Fe2+, I think of four old uncles arguing at my counter, each stubborn like an unpaired electron.
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